Solve for z -18=15z-9(2z-2)

$- 18 = 15 z - 9 (2 z - 2)$

Rewrite the equation as $15 z - 9 (2 z - 2) = - 18$ .

$15 z - 9 (2 z - 2) = - 18$

Simplify $15 z - 9 (2 z - 2)$ .

Simplify each term.

Apply the distributive property.

$15 z - 9 (2 z) - 9 \cdot - 2 = - 18$

Multiply $2$ by $- 9$ .

$15 z - 18 z - 9 \cdot - 2 = - 18$

Multiply $- 9$ by $- 2$ .

$15 z - 18 z + 18 = - 18$

Subtract $18 z$ from $15 z$ .

$- 3 z + 18 = - 18$

Move all terms not containing $z$ to the right side of the equation.

Subtract $18$ from both sides of the equation.

$- 3 z = - 18 - 18$

Subtract $18$ from $- 18$ .

$- 3 z = - 36$

Divide each term in $- 3 z = - 36$ by $- 3$ and simplify.

Divide each term in $- 3 z = - 36$ by $- 3$ .

$\frac{- 3 z}{- 3} = \frac{- 36}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 z}{- 3} = \frac{- 36}{- 3}$

Divide $z$ by $1$ .

$z = \frac{- 36}{- 3}$

Simplify the right side.

Divide $- 36$ by $- 3$ .

$z = 12$