Solve for z 2=(10+z)/-3

$2 = \frac{10 + z}{- 3}$

Step 1

Rewrite the equation as $\frac{10 + z}{- 3} = 2$ .

$\frac{10 + z}{- 3} = 2$

Step 2

Multiply both sides of the equation by $- 3$ .

$- 3 \frac{10 + z}{- 3} = - 3 \cdot 2$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 3 \frac{10 + z}{- 3}$ .

Cancel the common factor of $3$ .

Factor $3$ out of $- 3$ .

$3 (- 1) \frac{10 + z}{- 3} = - 3 \cdot 2$

Factor $3$ out of $- 3$ .

$3 \cdot - 1 \frac{10 + z}{3 \cdot - 1} = - 3 \cdot 2$

Cancel the common factor.

$3 \cdot - 1 \frac{10 + z}{3 \cdot - 1} = - 3 \cdot 2$

Rewrite the expression.

$- \frac{10 + z}{- 1} = - 3 \cdot 2$

Simplify the expression.

Move the negative one from the denominator of $\frac{10 + z}{- 1}$ .

$- (- 1 \cdot (10 + z)) = - 3 \cdot 2$

Rewrite $- 1 \cdot (10 + z)$ as $- (10 + z)$ .

$- - (10 + z) = - 3 \cdot 2$

Apply the distributive property.

$- (- 1 \cdot 10 - z) = - 3 \cdot 2$

Multiply $- 1$ by $10$ .

$- (- 10 - z) = - 3 \cdot 2$

Apply the distributive property.

$- - 10 - - z = - 3 \cdot 2$

Multiply $- 1$ by $- 10$ .

$10 - - z = - 3 \cdot 2$

Multiply $- - z$ .

Multiply $- 1$ by $- 1$ .

$10 + 1 z = - 3 \cdot 2$

Multiply $z$ by $1$ .

$10 + z = - 3 \cdot 2$

Simplify the right side.

Multiply $- 3$ by $2$ .

$10 + z = - 6$

Step 4

Move all terms not containing $z$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$z = - 6 - 10$

Subtract $10$ from $- 6$ .

$z = - 16$

Solve for z 2=(10+z)/-3

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