Solve for z 39-4z=28-8z+3

$39 - 4 z = 28 - 8 z + 3$

Step 1

Add $28$ and $3$ .

$39 - 4 z = - 8 z + 31$

Step 2

Move all terms containing $z$ to the left side of the equation.

Add $8 z$ to both sides of the equation.

$39 - 4 z + 8 z = 31$

Add $- 4 z$ and $8 z$ .

$39 + 4 z = 31$

Step 3

Move all terms not containing $z$ to the right side of the equation.

Subtract $39$ from both sides of the equation.

$4 z = 31 - 39$

Subtract $39$ from $31$ .

$4 z = - 8$

Step 4

Divide each term in $4 z = - 8$ by $4$ and simplify.

Divide each term in $4 z = - 8$ by $4$ .

$\frac{4 z}{4} = \frac{- 8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 z}{4} = \frac{- 8}{4}$

Divide $z$ by $1$ .

$z = \frac{- 8}{4}$

Simplify the right side.

Divide $- 8$ by $4$ .

$z = - 2$