Solve for z -5z-12=14+14-z

$- 5 z - 12 = 14 + 14 - z$

Add $14$ and $14$ .

$- 5 z - 12 = 28 - z$

Move all terms containing $z$ to the left side of the equation.

Add $z$ to both sides of the equation.

$- 5 z - 12 + z = 28$

Add $- 5 z$ and $z$ .

$- 4 z - 12 = 28$

Move all terms not containing $z$ to the right side of the equation.

Add $12$ to both sides of the equation.

$- 4 z = 28 + 12$

Add $28$ and $12$ .

$- 4 z = 40$

Divide each term in $- 4 z = 40$ by $- 4$ and simplify.

Divide each term in $- 4 z = 40$ by $- 4$ .

$\frac{- 4 z}{- 4} = \frac{40}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 z}{- 4} = \frac{40}{- 4}$

Divide $z$ by $1$ .

$z = \frac{40}{- 4}$

Simplify the right side.

Divide $40$ by $- 4$ .

$z = - 10$