Solve for z 6=1/4z-1

$6 = \frac{1}{4} z - 1$

Rewrite the equation as $\frac{1}{4} z - 1 = 6$ .

$\frac{1}{4} z - 1 = 6$

Combine $\frac{1}{4}$ and $z$ .

$\frac{z}{4} - 1 = 6$

Move all terms not containing $z$ to the right side of the equation.

Add $1$ to both sides of the equation.

$\frac{z}{4} = 6 + 1$

Add $6$ and $1$ .

$\frac{z}{4} = 7$

Multiply both sides of the equation by $4$ .

$4 \frac{z}{4} = 4 \cdot 7$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$4 \frac{z}{4} = 4 \cdot 7$

Rewrite the expression.

$z = 4 \cdot 7$

Simplify the right side.

Multiply $4$ by $7$ .

$z = 28$