Solve for z -7(2z-18)=-16z

$- 7 (2 z - 18) = - 16 z$

Step 1

Simplify $- 7 (2 z - 18)$ .

Start simplifying.

$0 + 0 - 7 (2 z - 18) = - 16 z$

Simplify by adding zeros.

$- 7 (2 z - 18) = - 16 z$

Apply the distributive property.

$- 7 (2 z) - 7 \cdot - 18 = - 16 z$

Multiply.

Multiply $2$ by $- 7$ .

$- 14 z - 7 \cdot - 18 = - 16 z$

Multiply $- 7$ by $- 18$ .

$- 14 z + 126 = - 16 z$

Step 2

Move all terms containing $z$ to the left side of the equation.

Add $16 z$ to both sides of the equation.

$- 14 z + 126 + 16 z = 0$

Add $- 14 z$ and $16 z$ .

$2 z + 126 = 0$

Step 3

Subtract $126$ from both sides of the equation.

$2 z = - 126$

Step 4

Divide each term in $2 z = - 126$ by $2$ and simplify.

Divide each term in $2 z = - 126$ by $2$ .

$\frac{2 z}{2} = \frac{- 126}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 z}{2} = \frac{- 126}{2}$

Divide $z$ by $1$ .

$z = \frac{- 126}{2}$

Simplify the right side.

Divide $- 126$ by $2$ .

$z = - 63$