Solve for z 7/8(y-z)=x

$\frac{7}{8} (y - z) = x$

Multiply both sides of the equation by $\frac{8}{7}$ .

$\frac{8}{7} (\frac{7}{8} \cdot (y - z)) = \frac{8}{7} x$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{8}{7} (\frac{7}{8} \cdot (y - z))$ .

Apply the distributive property.

$\frac{8}{7} (\frac{7}{8} y + \frac{7}{8} (- z)) = \frac{8}{7} x$

Combine $\frac{7}{8}$ and $y$ .

$\frac{8}{7} (\frac{7 y}{8} + \frac{7}{8} (- z)) = \frac{8}{7} x$

Combine $\frac{7}{8}$ and $z$ .

$\frac{8}{7} (\frac{7 y}{8} - \frac{7 z}{8}) = \frac{8}{7} x$

Apply the distributive property.

$\frac{8}{7} \cdot \frac{7 y}{8} + \frac{8}{7} (- \frac{7 z}{8}) = \frac{8}{7} x$

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8}{7} \cdot \frac{7 y}{8} + \frac{8}{7} (- \frac{7 z}{8}) = \frac{8}{7} x$

Rewrite the expression.

$\frac{1}{7} (7 y) + \frac{8}{7} (- \frac{7 z}{8}) = \frac{8}{7} x$

Cancel the common factor of $7$ .

Factor $7$ out of $7 y$ .

$\frac{1}{7} (7 (y)) + \frac{8}{7} (- \frac{7 z}{8}) = \frac{8}{7} x$

Cancel the common factor.

$\frac{1}{7} (7 y) + \frac{8}{7} (- \frac{7 z}{8}) = \frac{8}{7} x$

Rewrite the expression.

$y + \frac{8}{7} (- \frac{7 z}{8}) = \frac{8}{7} x$

Cancel the common factor of $8$ .

Move the leading negative in $- \frac{7 z}{8}$ into the numerator.

$y + \frac{8}{7} \cdot \frac{- 7 z}{8} = \frac{8}{7} x$

Cancel the common factor.

$y + \frac{8}{7} \cdot \frac{- 7 z}{8} = \frac{8}{7} x$

Rewrite the expression.

$y + \frac{1}{7} (- 7 z) = \frac{8}{7} x$

Cancel the common factor of $7$ .

Factor $7$ out of $- 7 z$ .

$y + \frac{1}{7} (7 (- z)) = \frac{8}{7} x$

Cancel the common factor.

$y + \frac{1}{7} (7 (- z)) = \frac{8}{7} x$

Rewrite the expression.

$y - z = \frac{8}{7} x$

Simplify the right side.

Combine $\frac{8}{7}$ and $x$ .

$y - z = \frac{8 x}{7}$

Subtract $y$ from both sides of the equation.

$- z = \frac{8 x}{7} - y$

Divide each term in $- z = \frac{8 x}{7} - y$ by $- 1$ and simplify.

Divide each term in $- z = \frac{8 x}{7} - y$ by $- 1$ .

$\frac{- z}{- 1} = \frac{\frac{8 x}{7}}{- 1} + \frac{- y}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{z}{1} = \frac{\frac{8 x}{7}}{- 1} + \frac{- y}{- 1}$

Divide $z$ by $1$ .

$z = \frac{\frac{8 x}{7}}{- 1} + \frac{- y}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{\frac{8 x}{7}}{- 1}$ .

$z = - 1 \cdot \frac{8 x}{7} + \frac{- y}{- 1}$

Rewrite $- 1 \cdot \frac{8 x}{7}$ as $- \frac{8 x}{7}$ .

$z = - \frac{8 x}{7} + \frac{- y}{- 1}$

Dividing two negative values results in a positive value.

$z = - \frac{8 x}{7} + \frac{y}{1}$

Divide $y$ by $1$ .

$z = - \frac{8 x}{7} + y$

Solve for z 7/8(y-z)=x

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