Solve for z 9(z-3)=12z

$9 (z - 3) = 12 z$

Step 1

Simplify $9 (z - 3)$ .

Rewrite.

$0 + 0 + 9 (z - 3) = 12 z$

Simplify by adding zeros.

$9 (z - 3) = 12 z$

Apply the distributive property.

$9 z + 9 \cdot - 3 = 12 z$

Multiply $9$ by $- 3$ .

$9 z - 27 = 12 z$

Step 2

Move all terms containing $z$ to the left side of the equation.

Subtract $12 z$ from both sides of the equation.

$9 z - 27 - 12 z = 0$

Subtract $12 z$ from $9 z$ .

$- 3 z - 27 = 0$

Step 3

Add $27$ to both sides of the equation.

$- 3 z = 27$

Step 4

Divide each term in $- 3 z = 27$ by $- 3$ and simplify.

Divide each term in $- 3 z = 27$ by $- 3$ .

$\frac{- 3 z}{- 3} = \frac{27}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 z}{- 3} = \frac{27}{- 3}$

Divide $z$ by $1$ .

$z = \frac{27}{- 3}$

Simplify the right side.

Divide $27$ by $- 3$ .

$z = - 9$