Solve in Terms of the Arbitrary Variable b a+bi=14+2i

$a + b i = 14 + 2 i$

Step 1

Subtract $b i$ from both sides of the equation.

$a = 14 + 2 i - b i$

Step 2

Solve the equation for $i$ .

Combine the opposite terms in $14 + 2 i - b i + b (i)$ .

Add $- b i$ and $b (i)$ .

$14 + 2 i + 0 = 14 + 2 i$

Add $14 + 2 i$ and $0$ .

$14 + 2 i = 14 + 2 i$

Move all terms containing $i$ to the left side of the equation.

Subtract $2 i$ from both sides of the equation.

$14 + 2 i - 2 i = 14$

Combine the opposite terms in $14 + 2 i - 2 i$ .

Subtract $2 i$ from $2 i$ .

$14 + 0 = 14$

Add $14$ and $0$ .

$14 = 14$

Since $14 = 14$ , the equation will always be true.

Always true