Solve in Terms of the Arbitrary Variable x 2x-3y+z=4 y-2z+x-5=0 3-2x=4y-z

$2 x - 3 y + z = 4$ $y - 2 z + x - 5 = 0$ $3 - 2 x = 4 y - z$

Solve the equation for $y$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $2 x$ from both sides of the equation.

$- 3 y + z = 4 - 2 x$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

Subtract $z$ from both sides of the equation.

$- 3 y = 4 - 2 x - z$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

$- 3 y = 4 - 2 x - z$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

Divide each term in $- 3 y = 4 - 2 x - z$ by $- 3$ and simplify.

Divide each term in $- 3 y = 4 - 2 x - z$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{4}{- 3} + \frac{- 2 x}{- 3} + \frac{- z}{- 3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{4}{- 3} + \frac{- 2 x}{- 3} + \frac{- z}{- 3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

Divide $y$ by $1$ .

$y = \frac{4}{- 3} + \frac{- 2 x}{- 3} + \frac{- z}{- 3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

$y = \frac{4}{- 3} + \frac{- 2 x}{- 3} + \frac{- z}{- 3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

$y = \frac{4}{- 3} + \frac{- 2 x}{- 3} + \frac{- z}{- 3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{4}{3} + \frac{- 2 x}{- 3} + \frac{- z}{- 3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

Dividing two negative values results in a positive value.

$y = - \frac{4}{3} + \frac{(2) x}{3} + \frac{- z}{- 3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

Dividing two negative values results in a positive value.

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$y - 2 z + x - 5 = 0$

$3 - 2 x = 4 y - z$

Solve the equation for $z$ .

Simplify $(- \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}) - 2 z + x - 5$ .

To write $- 5$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$(\frac{2 x}{3} + \frac{z}{3}) - 2 z + x - \frac{4}{3} - 5 \cdot \frac{3}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Combine $- 5$ and $\frac{3}{3}$ .

$(\frac{2 x}{3} + \frac{z}{3}) - 2 z + x - \frac{4}{3} + \frac{- 5 \cdot 3}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Combine the numerators over the common denominator.

$(\frac{2 x}{3} + \frac{z}{3}) - 2 z + x + \frac{- 4 - 5 \cdot 3}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify the numerator.

Multiply $- 5$ by $3$ .

$(\frac{2 x}{3} + \frac{z}{3}) - 2 z + x + \frac{- 4 - 15}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Subtract $15$ from $- 4$ .

$(\frac{2 x}{3} + \frac{z}{3}) - 2 z + x + \frac{- 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$(\frac{2 x}{3} + \frac{z}{3}) - 2 z + x + \frac{- 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Move the negative in front of the fraction.

$(\frac{2 x}{3} + \frac{z}{3}) - 2 z + x - \frac{19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

To write $x$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$(\frac{z}{3}) - 2 z + \frac{2 x}{3} + x \cdot \frac{3}{3} - \frac{19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify terms.

Combine $x$ and $\frac{3}{3}$ .

$(\frac{z}{3}) - 2 z + \frac{2 x}{3} + \frac{x \cdot 3}{3} - \frac{19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Combine the numerators over the common denominator.

$(\frac{z}{3}) - 2 z + \frac{2 x + x \cdot 3}{3} - \frac{19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Combine the numerators over the common denominator.

$- 2 z + \frac{z + 2 x + x \cdot 3 - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$- 2 z + \frac{z + 2 x + x \cdot 3 - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Move $3$ to the left of $x$ .

$- 2 z + \frac{z + 2 x + 3 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Add $2 x$ and $3 x$ .

$- 2 z + \frac{z + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

To write $- 2 z$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- 2 z \cdot \frac{3}{3} + \frac{z + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify terms.

Combine $- 2 z$ and $\frac{3}{3}$ .

$\frac{- 2 z \cdot 3}{3} + \frac{z + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Combine the numerators over the common denominator.

$\frac{- 2 z \cdot 3 + z + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$\frac{- 2 z \cdot 3 + z + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify the numerator.

Multiply $3$ by $- 2$ .

$\frac{- 6 z + z + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Add $- 6 z$ and $z$ .

$\frac{- 5 z + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$\frac{- 5 z + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify with factoring out.

Factor $- 1$ out of $- 5 z$ .

$\frac{- (5 z) + 5 x - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Factor $- 1$ out of $5 x$ .

$\frac{- (5 z) - (- 5 x) - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Factor $- 1$ out of $- (5 z) - (- 5 x)$ .

$\frac{- (5 z - 5 x) - 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Rewrite $- 19$ as $- 1 (19)$ .

$\frac{- (5 z - 5 x) - 1 \cdot 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Factor $- 1$ out of $- (5 z - 5 x) - 1 (19)$ .

$\frac{- (5 z - 5 x + 19)}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify the expression.

Rewrite $- (5 z - 5 x + 19)$ as $- 1 (5 z - 5 x + 19)$ .

$\frac{- 1 (5 z - 5 x + 19)}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Move the negative in front of the fraction.

$- \frac{5 z - 5 x + 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$- \frac{5 z - 5 x + 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$- \frac{5 z - 5 x + 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$- \frac{5 z - 5 x + 19}{3} = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Set the numerator equal to zero.

$5 z - 5 x + 19 = 0$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Solve the equation for $z$ .

Move all terms not containing $z$ to the right side of the equation.

Add $5 x$ to both sides of the equation.

$5 z + 19 = 5 x$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Subtract $19$ from both sides of the equation.

$5 z = 5 x - 19$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$5 z = 5 x - 19$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Divide each term in $5 z = 5 x - 19$ by $5$ and simplify.

Divide each term in $5 z = 5 x - 19$ by $5$ .

$\frac{5 z}{5} = \frac{5 x}{5} + \frac{- 19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 z}{5} = \frac{5 x}{5} + \frac{- 19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Divide $z$ by $1$ .

$z = \frac{5 x}{5} + \frac{- 19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$z = \frac{5 x}{5} + \frac{- 19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$z = \frac{5 x}{5} + \frac{- 19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify the right side.

Simplify each term.

Cancel the common factor of $5$ .

Cancel the common factor.

$z = \frac{5 x}{5} + \frac{- 19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Divide $x$ by $1$ .

$z = x + \frac{- 19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$z = x + \frac{- 19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Move the negative in front of the fraction.

$z = x - \frac{19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$z = x - \frac{19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$z = x - \frac{19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$z = x - \frac{19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$z = x - \frac{19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

$z = x - \frac{19}{5}$

$y = - \frac{4}{3} + \frac{2 x}{3} + \frac{z}{3}$

$3 - 2 x = 4 y - z$

Simplify the right side.

Simplify $- \frac{4}{3} + \frac{2 x}{3} + \frac{x - \frac{19}{5}}{3}$ .

Combine the numerators over the common denominator.

$y = \frac{- 4 + 2 x + x - \frac{19}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

To write $- 4$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$y = \frac{2 x + x - 4 \cdot \frac{5}{5} - \frac{19}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Combine $- 4$ and $\frac{5}{5}$ .

$y = \frac{2 x + x + \frac{- 4 \cdot 5}{5} - \frac{19}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Combine the numerators over the common denominator.

$y = \frac{2 x + x + \frac{- 4 \cdot 5 - 19}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Simplify the numerator.

Multiply $- 4$ by $5$ .

$y = \frac{2 x + x + \frac{- 20 - 19}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Subtract $19$ from $- 20$ .

$y = \frac{2 x + x + \frac{- 39}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

$y = \frac{2 x + x + \frac{- 39}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Move the negative in front of the fraction.

$y = \frac{2 x + x - \frac{39}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Add $2 x$ and $x$ .

$y = \frac{3 x - \frac{39}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Cancel the common factor of $3 x - \frac{39}{5}$ and $3$ .

Factor $- 1$ out of $3 x$ .

$y = \frac{- (- 3 x) - \frac{39}{5}}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Factor $- 1$ out of $- \frac{39}{5}$ .

$y = \frac{- (- 3 x) - (\frac{39}{5})}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Factor $- 1$ out of $- (- 3 x) - (\frac{39}{5})$ .

$y = \frac{- (- 3 x + \frac{39}{5})}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Rewrite $- (- 3 x + \frac{39}{5})$ as $- 1 (- 3 x + \frac{39}{5})$ .

$y = \frac{- 1 (- 3 x + \frac{39}{5})}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Factor $3$ out of $- 1 (- 3 x + \frac{39}{5})$ .

$y = \frac{3 (- 1 (- x + \frac{13}{5}))}{3}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Cancel the common factors.

Factor $3$ out of $3$ .

$y = \frac{3 (- 1 (- x + \frac{13}{5}))}{3 (1)}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Cancel the common factor.

$y = \frac{3 (- 1 (- x + \frac{13}{5}))}{3 \cdot 1}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Rewrite the expression.

$y = \frac{- 1 (- x + \frac{13}{5})}{1}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Divide $- 1 (- x + \frac{13}{5})$ by $1$ .

$y = - 1 (- x + \frac{13}{5})$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

$y = - 1 (- x + \frac{13}{5})$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

$y = - 1 (- x + \frac{13}{5})$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Rewrite $- 1 (- x + \frac{13}{5})$ as $- (- x + \frac{13}{5})$ .

$y = - (- x + \frac{13}{5})$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Apply the distributive property.

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Multiply $- - x$ .

Multiply $- 1$ by $- 1$ .

$y = 1 x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Multiply $x$ by $1$ .

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 y - z$

Simplify the right side.

Simplify $4 (x - \frac{13}{5}) - (x - \frac{19}{5})$ .

Simplify each term.

Apply the distributive property.

$3 - 2 x = 4 x + 4 (- \frac{13}{5}) - (x - \frac{19}{5})$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Multiply $4 (- \frac{13}{5})$ .

Multiply $- 1$ by $4$ .

$3 - 2 x = 4 x - 4 (\frac{13}{5}) - (x - \frac{19}{5})$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Combine $- 4$ and $\frac{13}{5}$ .

$3 - 2 x = 4 x + \frac{- 4 \cdot 13}{5} - (x - \frac{19}{5})$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Multiply $- 4$ by $13$ .

$3 - 2 x = 4 x + \frac{- 52}{5} - (x - \frac{19}{5})$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 x + \frac{- 52}{5} - (x - \frac{19}{5})$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Move the negative in front of the fraction.

$3 - 2 x = 4 x - \frac{52}{5} - (x - \frac{19}{5})$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Apply the distributive property.

$3 - 2 x = 4 x - \frac{52}{5} - x + \frac{19}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Multiply $- - \frac{19}{5}$ .

Multiply $- 1$ by $- 1$ .

$3 - 2 x = 4 x - \frac{52}{5} - x + 1 (\frac{19}{5})$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Multiply $\frac{19}{5}$ by $1$ .

$3 - 2 x = 4 x - \frac{52}{5} - x + \frac{19}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 x - \frac{52}{5} - x + \frac{19}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 x - \frac{52}{5} - x + \frac{19}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Simplify terms.

Combine the numerators over the common denominator.

$3 - 2 x = 4 x - x + \frac{- 52 + 19}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Simplify the expression.

Add $- 52$ and $19$ .

$3 - 2 x = 4 x - x + \frac{- 33}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Move the negative in front of the fraction.

$3 - 2 x = 4 x - x - \frac{33}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 4 x - x - \frac{33}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

Subtract $x$ from $4 x$ .

$3 - 2 x = 3 x - \frac{33}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

The simplified system is the arbitrary solution of the original system of equations.

$y = x - \frac{13}{5}$

$z = x - \frac{19}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Reduce the system.

$z = (\frac{48}{25}) - \frac{19}{5}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Simplify the right side.

Simplify $(\frac{48}{25}) - \frac{19}{5}$ .

To write $- \frac{19}{5}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$z = \frac{48}{25} - \frac{19}{5} \cdot \frac{5}{5}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Write each expression with a common denominator of $25$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{19}{5}$ by $\frac{5}{5}$ .

$z = \frac{48}{25} - \frac{19 \cdot 5}{5 \cdot 5}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Multiply $5$ by $5$ .

$z = \frac{48}{25} - \frac{19 \cdot 5}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

$z = \frac{48}{25} - \frac{19 \cdot 5}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Combine the numerators over the common denominator.

$z = \frac{48 - 19 \cdot 5}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Simplify the numerator.

Multiply $- 19$ by $5$ .

$z = \frac{48 - 95}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Subtract $95$ from $48$ .

$z = \frac{- 47}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

$z = \frac{- 47}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Move the negative in front of the fraction.

$z = - \frac{47}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

$z = - \frac{47}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

$z = - \frac{47}{25}$

$y = (\frac{48}{25}) - \frac{13}{5}$

$3 - 2 x = 3 x - \frac{33}{5}$

Simplify the right side.

Simplify $(\frac{48}{25}) - \frac{13}{5}$ .

To write $- \frac{13}{5}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$y = \frac{48}{25} - \frac{13}{5} \cdot \frac{5}{5}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

Write each expression with a common denominator of $25$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{13}{5}$ by $\frac{5}{5}$ .

$y = \frac{48}{25} - \frac{13 \cdot 5}{5 \cdot 5}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

Multiply $5$ by $5$ .

$y = \frac{48}{25} - \frac{13 \cdot 5}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

$y = \frac{48}{25} - \frac{13 \cdot 5}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

Combine the numerators over the common denominator.

$y = \frac{48 - 13 \cdot 5}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

Simplify the numerator.

Multiply $- 13$ by $5$ .

$y = \frac{48 - 65}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

Subtract $65$ from $48$ .

$y = \frac{- 17}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

$y = \frac{- 17}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

Move the negative in front of the fraction.

$y = - \frac{17}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

$y = - \frac{17}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

$y = - \frac{17}{25}$

$z = - \frac{47}{25}$

$3 - 2 x = 3 x - \frac{33}{5}$

Simplify the left side.

Reorder $3$ and $- 2 x$ .

$- 2 x + 3 = 3 x - \frac{33}{5}$

$z = - \frac{47}{25}$

$y = - \frac{17}{25}$

$- 2 x + 3 = 3 x - \frac{33}{5}$

$z = - \frac{47}{25}$

$y = - \frac{17}{25}$

Solve in Terms of the Arbitrary Variable x 2x-3y+z=4 y-2z+x-5=0 3-2x=4y-z

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