Solve the Absolute Value Inequality for d 3-5|2d-3|=4

$3 - 5 | 2 d - 3 | = 4$

Move all terms not containing $| 2 d - 3 |$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- 5 | 2 d - 3 | = 4 - 3$

Subtract $3$ from $4$ .

$- 5 | 2 d - 3 | = 1$

Divide each term in $- 5 | 2 d - 3 | = 1$ by $- 5$ and simplify.

Divide each term in $- 5 | 2 d - 3 | = 1$ by $- 5$ .

$\frac{- 5 | 2 d - 3 |}{- 5} = \frac{1}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 | 2 d - 3 |}{- 5} = \frac{1}{- 5}$

Divide $| 2 d - 3 |$ by $1$ .

$| 2 d - 3 | = \frac{1}{- 5}$

Simplify the right side.

Move the negative in front of the fraction.

$| 2 d - 3 | = - \frac{1}{5}$

There is no value of $d$ that makes the equation be true since an absolute value can never be negative.

No solution