Solve the Absolute Value Inequality for x -5|x-4|>-20

$- 5 | x - 4 | > - 20$

Divide each term in $- 5 | x - 4 | > - 20$ by $- 5$ and simplify.

Divide each term in $- 5 | x - 4 | > - 20$ by $- 5$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 5 | x - 4 |}{- 5} < \frac{- 20}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 | x - 4 |}{- 5} < \frac{- 20}{- 5}$

Divide $| x - 4 |$ by $1$ .

$| x - 4 | < \frac{- 20}{- 5}$

Simplify the right side.

Divide $- 20$ by $- 5$ .

$| x - 4 | < 4$

Write $| x - 4 | < 4$ as a piecewise.

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$x - 4 \geq 0$

Add $4$ to both sides of the inequality.

$x \geq 4$

In the piece where $x - 4$ is non-negative, remove the absolute value.

$x - 4 < 4$

To find the interval for the second piece, find where the inside of the absolute value is negative.

$x - 4 < 0$

Add $4$ to both sides of the inequality.

$x < 4$

In the piece where $x - 4$ is negative, remove the absolute value and multiply by $- 1$ .

$- (x - 4) < 4$

Write as a piecewise.

${\begin{cases} x - 4 < 4 & x \geq 4 \\ - (x - 4) < 4 & x < 4 \end{cases}$

Simplify $- (x - 4) < 4$ .

Apply the distributive property.

${\begin{cases} x - 4 < 4 & x \geq 4 \\ - x - - 4 < 4 & x < 4 \end{cases}$

Multiply $- 1$ by $- 4$ .

${\begin{cases} x - 4 < 4 & x \geq 4 \\ - x + 4 < 4 & x < 4 \end{cases}$

Solve $x - 4 < 4$ when $x \geq 4$ .

Move all terms not containing $x$ to the right side of the inequality.

Add $4$ to both sides of the inequality.

$x < 4 + 4$

Add $4$ and $4$ .

$x < 8$

Find the intersection of $x < 8$ and $x \geq 4$ .

$4 \leq x < 8$

Solve $- x + 4 < 4$ when $x < 4$ .

Solve $- x + 4 < 4$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Subtract $4$ from both sides of the inequality.

$- x < 4 - 4$

Subtract $4$ from $4$ .

$- x < 0$

Divide each term in $- x < 0$ by $- 1$ and simplify.

Divide each term in $- x < 0$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} > \frac{0}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} > \frac{0}{- 1}$

Divide $x$ by $1$ .

$x > \frac{0}{- 1}$

Simplify the right side.

Divide $0$ by $- 1$ .

$x > 0$

Find the intersection of $x > 0$ and $x < 4$ .

$0 < x < 4$

Find the union of the solutions.

$0 < x < 8$

The result can be shown in multiple forms.

Inequality Form:

$0 < x < 8$

Interval Notation:

$(0, 8)$

Solve the Absolute Value Inequality for x -5|x-4|>-20

Related Questions

Support LCMGCF.com by disabling your adblocker.