Solve the Function Operation f(x)=0.02x^2+0.07x+30.4 , f(10)

$f (x) = 0.02 x^{2} + 0.07 x + 30.4$ , $f (10)$

Step 1

Replace the variable $x$ with $10$ in the expression.

$f (10) = 0.02 {(10)}^{2} + 0.07 (10) + 30.4$

Step 2

Simplify $0.02 {(10)}^{2} + 0.07 (10) + 30.4$ .

Remove parentheses.

$0.02 {(10)}^{2} + 0.07 (10) + 30.4$

Simplify each term.

Raise $10$ to the power of $2$ .

$0.02 \cdot 100 + 0.07 (10) + 30.4$

Multiply $0.02$ by $100$ .

$2 + 0.07 (10) + 30.4$

Multiply $0.07$ by $10$ .

$2 + 0.7 + 30.4$

Simplify by adding numbers.

Add $2$ and $0.7$ .

$2.7 + 30.4$

Add $2.7$ and $30.4$ .

$33.1$