Solve the Function Operation f(x)=6x-12 g(x)=5x+1 h(x)=x^2-4 (f+g)(x)

$f (x) = 6 x - 12$ $g (x) = 5 x + 1$ $h (x) = x^{2} - 4$ $(f + g) (x)$

Step 1

Evaluate $f + g$ .

Replace the function designators in $f + g$ with the actual functions.

$6 x - 12 + 5 x + 1$

Remove parentheses.

$6 x - 12 + 5 x + 1$

Add $6 x$ and $5 x$ .

$11 x - 12 + 1$

Add $- 12$ and $1$ .

$11 x - 11$

Step 2

Evaluate $f + g$ at $x$ .

$11 (x) - 11$

Step 3

Simplify $11 (x) - 11$ .

Remove parentheses.

$11 (x) - 11$

Multiply $11$ by $x$ .

$11 x - 11$