Solve the Inequality for a 3a<-16

$3 a < - 16$

Divide each term in $3 a < - 16$ by $3$ .

$\frac{3 a}{3} < \frac{- 16}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 a}{3} < \frac{- 16}{3}$

Divide $a$ by $1$ .

$a < \frac{- 16}{3}$

$a < \frac{- 16}{3}$

$a < \frac{- 16}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$a < - \frac{16}{3}$

$a < - \frac{16}{3}$

The result can be shown in multiple forms.

Inequality Form:

$a < - \frac{16}{3}$

Interval Notation:

$(- \infty, - \frac{16}{3})$

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