Solve the Inequality for a 3a+7<=16

$3 a + 7 \leq 16$

Step 1

Move all terms not containing $a$ to the right side of the inequality.

Subtract $7$ from both sides of the inequality.

$3 a \leq 16 - 7$

Subtract $7$ from $16$ .

$3 a \leq 9$

Step 2

Divide each term in $3 a \leq 9$ by $3$ and simplify.

Divide each term in $3 a \leq 9$ by $3$ .

$\frac{3 a}{3} \leq \frac{9}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 a}{3} \leq \frac{9}{3}$

Divide $a$ by $1$ .

$a \leq \frac{9}{3}$

Simplify the right side.

Divide $9$ by $3$ .

$a \leq 3$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$a \leq 3$

Interval Notation:

$(- \infty, 3]$