Solve the Inequality for a 3a+8+5a>4a-16

$3 a + 8 + 5 a > 4 a - 16$

Step 1

Add $3 a$ and $5 a$ .

$8 a + 8 > 4 a - 16$

Step 2

Move all terms containing $a$ to the left side of the inequality.

Subtract $4 a$ from both sides of the inequality.

$8 a + 8 - 4 a > - 16$

Subtract $4 a$ from $8 a$ .

$4 a + 8 > - 16$

Step 3

Move all terms not containing $a$ to the right side of the inequality.

Subtract $8$ from both sides of the inequality.

$4 a > - 16 - 8$

Subtract $8$ from $- 16$ .

$4 a > - 24$

Step 4

Divide each term in $4 a > - 24$ by $4$ and simplify.

Divide each term in $4 a > - 24$ by $4$ .

$\frac{4 a}{4} > \frac{- 24}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 a}{4} > \frac{- 24}{4}$

Divide $a$ by $1$ .

$a > \frac{- 24}{4}$

Simplify the right side.

Divide $- 24$ by $4$ .

$a > - 6$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$a > - 6$

Interval Notation:

$(- 6, \infty)$