Solve the Inequality for b 12>=-3b

$12 \geq - 3 b$

Rewrite so $b$ is on the left side of the inequality.

$- 3 b \leq 12$

Divide each term in $- 3 b \leq 12$ by $- 3$ and simplify.

Divide each term in $- 3 b \leq 12$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 b}{- 3} \geq \frac{12}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 b}{- 3} \geq \frac{12}{- 3}$

Divide $b$ by $1$ .

$b \geq \frac{12}{- 3}$

Simplify the right side.

Divide $12$ by $- 3$ .

$b \geq - 4$

The result can be shown in multiple forms.

Inequality Form:

$b \geq - 4$

Interval Notation:

$[- 4, \infty)$

Solve the Inequality for b 12>=-3b

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