Solve the Inequality for b 3+b/9<4

$3 + \frac{b}{9} < 4$

Move all terms not containing $b$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$\frac{b}{9} < 4 - 3$

Subtract $3$ from $4$ .

$\frac{b}{9} < 1$

Multiply both sides by $9$ .

$\frac{b}{9} \cdot 9 < 1 \cdot 9$

Simplify.

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{b}{9} \cdot 9 < 1 \cdot 9$

Rewrite the expression.

$b < 1 \cdot 9$

Simplify the right side.

Multiply $9$ by $1$ .

$b < 9$

The result can be shown in multiple forms.

Inequality Form:

$b < 9$

Interval Notation:

$(- \infty, 9)$