Solve the Inequality for b 3b<=12

$3 b \leq 12$

Step 1

Divide each term in $3 b \leq 12$ by $3$ .

$\frac{3 b}{3} \leq \frac{12}{3}$

Step 2

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 b}{3} \leq \frac{12}{3}$

Divide $b$ by $1$ .

$b \leq \frac{12}{3}$

$b \leq \frac{12}{3}$

$b \leq \frac{12}{3}$

Step 3

Simplify the right side.

Divide $12$ by $3$ .

$b \leq 4$

$b \leq 4$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$b \leq 4$

Interval Notation:

$(- \infty, 4]$

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