Solve the Inequality for b -3b-4<=3b+3

$- 3 b - 4 \leq 3 b + 3$

Step 1

Move all terms containing $b$ to the left side of the inequality.

Subtract $3 b$ from both sides of the inequality.

$- 3 b - 4 - 3 b \leq 3$

Subtract $3 b$ from $- 3 b$ .

$- 6 b - 4 \leq 3$

Step 2

Move all terms not containing $b$ to the right side of the inequality.

Add $4$ to both sides of the inequality.

$- 6 b \leq 3 + 4$

Add $3$ and $4$ .

$- 6 b \leq 7$

Step 3

Divide each term in $- 6 b \leq 7$ by $- 6$ and simplify.

Divide each term in $- 6 b \leq 7$ by $- 6$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 6 b}{- 6} \geq \frac{7}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 b}{- 6} \geq \frac{7}{- 6}$

Divide $b$ by $1$ .

$b \geq \frac{7}{- 6}$

Simplify the right side.

Move the negative in front of the fraction.

$b \geq - \frac{7}{6}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$b \geq - \frac{7}{6}$

Interval Notation:

$[- \frac{7}{6}, \infty)$

Solve the Inequality for b -3b-4<=3b+3

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