Solve the Inequality for c 2(5c-4)>=5(2c+8)

$2 (5 c - 4) \geq 5 (2 c + 8)$

Simplify $2 (5 c - 4)$ .

Start simplifying.

$0 + 0 + 2 (5 c - 4) \geq 5 (2 c + 8)$

Simplify by adding zeros.

$2 (5 c - 4) \geq 5 (2 c + 8)$

Apply the distributive property.

$2 (5 c) + 2 \cdot - 4 \geq 5 (2 c + 8)$

Multiply.

Multiply $5$ by $2$ .

$10 c + 2 \cdot - 4 \geq 5 (2 c + 8)$

Multiply $2$ by $- 4$ .

$10 c - 8 \geq 5 (2 c + 8)$

Simplify $5 (2 c + 8)$ .

Apply the distributive property.

$10 c - 8 \geq 5 (2 c) + 5 \cdot 8$

Multiply.

Multiply $2$ by $5$ .

$10 c - 8 \geq 10 c + 5 \cdot 8$

Multiply $5$ by $8$ .

$10 c - 8 \geq 10 c + 40$

Move all terms containing $c$ to the left side of the inequality.

Subtract $10 c$ from both sides of the inequality.

$10 c - 8 - 10 c \geq 40$

Combine the opposite terms in $10 c - 8 - 10 c$ .

Subtract $10 c$ from $10 c$ .

$0 - 8 \geq 40$

Subtract $8$ from $0$ .

$- 8 \geq 40$

Since $- 8 \neq 40$ , there are no solutions.

No solution