Solve the Inequality for d 3d-7>=8

$3 d - 7 \geq 8$

Move all terms not containing $d$ to the right side of the inequality.

Add $7$ to both sides of the inequality.

$3 d \geq 8 + 7$

Add $8$ and $7$ .

$3 d \geq 15$

Divide each term in $3 d \geq 15$ by $3$ and simplify.

Divide each term in $3 d \geq 15$ by $3$ .

$\frac{3 d}{3} \geq \frac{15}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 d}{3} \geq \frac{15}{3}$

Divide $d$ by $1$ .

$d \geq \frac{15}{3}$

Simplify the right side.

Divide $15$ by $3$ .

$d \geq 5$

The result can be shown in multiple forms.

Inequality Form:

$d \geq 5$

Interval Notation:

$[5, \infty)$