Solve the Inequality for d 4-d<4+d

$4 - d < 4 + d$

Step 1

Move all terms containing $d$ to the left side of the inequality.

Subtract $d$ from both sides of the inequality.

$4 - d - d < 4$

Subtract $d$ from $- d$ .

$4 - 2 d < 4$

Step 2

Move all terms not containing $d$ to the right side of the inequality.

Subtract $4$ from both sides of the inequality.

$- 2 d < 4 - 4$

Subtract $4$ from $4$ .

$- 2 d < 0$

Step 3

Divide each term in $- 2 d < 0$ by $- 2$ and simplify.

Divide each term in $- 2 d < 0$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 d}{- 2} > \frac{0}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 d}{- 2} > \frac{0}{- 2}$

Divide $d$ by $1$ .

$d > \frac{0}{- 2}$

Simplify the right side.

Divide $0$ by $- 2$ .

$d > 0$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$d > 0$

Interval Notation:

$(0, \infty)$

Solve the Inequality for d 4-d<4+d

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