Solve the Inequality for d 5d+2(d-3)>36

$5 d + 2 (d - 3) > 36$

Step 1

Simplify $5 d + 2 (d - 3)$ .

Simplify each term.

Apply the distributive property.

$5 d + 2 d + 2 \cdot - 3 > 36$

Multiply $2$ by $- 3$ .

$5 d + 2 d - 6 > 36$

Add $5 d$ and $2 d$ .

$7 d - 6 > 36$

Step 2

Move all terms not containing $d$ to the right side of the inequality.

Add $6$ to both sides of the inequality.

$7 d > 36 + 6$

Add $36$ and $6$ .

$7 d > 42$

Step 3

Divide each term in $7 d > 42$ by $7$ and simplify.

Divide each term in $7 d > 42$ by $7$ .

$\frac{7 d}{7} > \frac{42}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 d}{7} > \frac{42}{7}$

Divide $d$ by $1$ .

$d > \frac{42}{7}$

Simplify the right side.

Divide $42$ by $7$ .

$d > 6$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$d > 6$

Interval Notation:

$(6, \infty)$