Solve the Inequality for D 5D-8D-4<=-4+3d

$5 D - 8 D - 4 \leq - 4 + 3 d$

Step 1

Subtract $8 D$ from $5 D$ .

$- 3 D - 4 \leq - 4 + 3 d$

Step 2

Move all terms not containing $D$ to the right side of the inequality.

Add $4$ to both sides of the inequality.

$- 3 D \leq - 4 + 3 d + 4$

Combine the opposite terms in $- 4 + 3 d + 4$ .

Add $- 4$ and $4$ .

$- 3 D \leq 3 d + 0$

Add $3 d$ and $0$ .

$- 3 D \leq 3 d$

Step 3

Divide each term in $- 3 D \leq 3 d$ by $- 3$ and simplify.

Divide each term in $- 3 D \leq 3 d$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 D}{- 3} \geq \frac{3 d}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 D}{- 3} \geq \frac{3 d}{- 3}$

Divide $D$ by $1$ .

$D \geq \frac{3 d}{- 3}$

Simplify the right side.

Cancel the common factor of $3$ and $- 3$ .

Factor $3$ out of $3 d$ .

$D \geq \frac{3 (d)}{- 3}$

Move the negative one from the denominator of $\frac{d}{- 1}$ .

$D \geq - 1 \cdot d$

Rewrite $- 1 \cdot d$ as $- d$ .

$D \geq - d$

Solve the Inequality for D 5D-8D-4<=-4+3d

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