Solve the Inequality for d 9-4d>=-3

$9 - 4 d \geq - 3$

Move all terms not containing $d$ to the right side of the inequality.

Subtract $9$ from both sides of the inequality.

$- 4 d \geq - 3 - 9$

Subtract $9$ from $- 3$ .

$- 4 d \geq - 12$

Divide each term in $- 4 d \geq - 12$ by $- 4$ and simplify.

Divide each term in $- 4 d \geq - 12$ by $- 4$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 4 d}{- 4} \leq \frac{- 12}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 d}{- 4} \leq \frac{- 12}{- 4}$

Divide $d$ by $1$ .

$d \leq \frac{- 12}{- 4}$

Simplify the right side.

Divide $- 12$ by $- 4$ .

$d \leq 3$

The result can be shown in multiple forms.

Inequality Form:

$d \leq 3$

Interval Notation:

$(- \infty, 3]$

Solve the Inequality for d 9-4d>=-3

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