Solve the Inequality for f 3(2-f)<=15

$3 (2 - f) \leq 15$

Divide each term in $3 (2 - f) \leq 15$ by $3$ and simplify.

Divide each term in $3 (2 - f) \leq 15$ by $3$ .

$\frac{3 (2 - f)}{3} \leq \frac{15}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (2 - f)}{3} \leq \frac{15}{3}$

Divide $2 - f$ by $1$ .

$2 - f \leq \frac{15}{3}$

Simplify the right side.

Divide $15$ by $3$ .

$2 - f \leq 5$

Move all terms not containing $f$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$- f \leq 5 - 2$

Subtract $2$ from $5$ .

$- f \leq 3$

Divide each term in $- f \leq 3$ by $- 1$ and simplify.

Divide each term in $- f \leq 3$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- f}{- 1} \geq \frac{3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{f}{1} \geq \frac{3}{- 1}$

Divide $f$ by $1$ .

$f \geq \frac{3}{- 1}$

Simplify the right side.

Divide $3$ by $- 1$ .

$f \geq - 3$

The result can be shown in multiple forms.

Inequality Form:

$f \geq - 3$

Interval Notation:

$[- 3, \infty)$

Solve the Inequality for f 3(2-f)<=15

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