Solve the Inequality for f 7/8f<=-1

$\frac{7}{8} f \leq - 1$

Multiply each term in $\frac{7}{8} f \leq - 1$ by $\frac{8}{7}$ .

$\frac{7}{8} f \frac{8}{7} \leq - \frac{8}{7}$

Simplify the left side.

Combine $\frac{7}{8}$ and $f$ .

$\frac{7 f}{8} \cdot \frac{8}{7} \leq - \frac{8}{7}$

Cancel the common factor of $7$ .

Factor $7$ out of $7 f$ .

$\frac{7 (f)}{8} \cdot \frac{8}{7} \leq - \frac{8}{7}$

Cancel the common factor.

$\frac{7 f}{8} \cdot \frac{8}{7} \leq - \frac{8}{7}$

Rewrite the expression.

$\frac{f}{8} \cdot 8 \leq - \frac{8}{7}$

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{f}{8} \cdot 8 \leq - \frac{8}{7}$

Rewrite the expression.

$f \leq - \frac{8}{7}$

The result can be shown in multiple forms.

Inequality Form:

$f \leq - \frac{8}{7}$

Interval Notation:

$(- \infty, - \frac{8}{7}]$