Solve the Inequality for f f+11<=5/3

$f + 11 \leq \frac{5}{3}$

Subtract $11$ from both sides of the inequality.

$f \leq \frac{5}{3} - 11$

To write $- 11$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f \leq \frac{5}{3} - 11 \cdot \frac{3}{3}$

Combine $- 11$ and $\frac{3}{3}$ .

$f \leq \frac{5}{3} + \frac{- 11 \cdot 3}{3}$

Combine the numerators over the common denominator.

$f \leq \frac{5 - 11 \cdot 3}{3}$

Simplify the numerator.

Multiply $- 11$ by $3$ .

$f \leq \frac{5 - 33}{3}$

Subtract $33$ from $5$ .

$f \leq \frac{- 28}{3}$

Move the negative in front of the fraction.

$f \leq - \frac{28}{3}$

The result can be shown in multiple forms.

Inequality Form:

$f \leq - \frac{28}{3}$

Interval Notation:

$(- \infty, - \frac{28}{3}]$