Solve the Inequality for g 2>=g/-4

$2 \geq \frac{g}{- 4}$

Step 1

Multiply both sides by $- 4$ .

$2 \cdot - 4 \leq \frac{g}{- 4} \cdot - 4$

Step 2

Simplify.

Simplify the left side.

Multiply $2$ by $- 4$ .

$- 8 \leq \frac{g}{- 4} \cdot - 4$

Simplify the right side.

Simplify $\frac{g}{- 4} \cdot - 4$ .

Cancel the common factor of $4$ .

Factor $4$ out of $- 4$ .

$- 8 \leq \frac{g}{4 (- 1)} \cdot - 4$

Factor $4$ out of $- 4$ .

$- 8 \leq \frac{g}{4 \cdot - 1} \cdot (4 \cdot - 1)$

Cancel the common factor.

$- 8 \leq \frac{g}{4 \cdot - 1} \cdot (4 \cdot - 1)$

Rewrite the expression.

$- 8 \leq \frac{g}{- 1} \cdot - 1$

Combine $\frac{g}{- 1}$ and $- 1$ .

$- 8 \leq \frac{g \cdot - 1}{- 1}$

Simplify the expression.

Move the negative one from the denominator of $\frac{g \cdot - 1}{- 1}$ .

$- 8 \leq - 1 \cdot (g \cdot - 1)$

Rewrite $- 1 \cdot (g \cdot - 1)$ as $- (g \cdot - 1)$ .

$- 8 \leq - (g \cdot - 1)$

Move $- 1$ to the left of $g$ .

$- 8 \leq - (- 1 \cdot g)$

Rewrite $- 1 g$ as $- g$ .

$- 8 \leq - - g$

Multiply $- - g$ .

Multiply $- 1$ by $- 1$ .

$- 8 \leq 1 g$

Multiply $g$ by $1$ .

$- 8 \leq g$

Step 3

Rewrite so $g$ is on the left side of the inequality.

$g \geq - 8$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$g \geq - 8$

Interval Notation:

$[- 8, \infty)$