Solve the Inequality for g 4g-3<7g+1

$4 g - 3 < 7 g + 1$

Move all terms containing $g$ to the left side of the inequality.

Subtract $7 g$ from both sides of the inequality.

$4 g - 3 - 7 g < 1$

Subtract $7 g$ from $4 g$ .

$- 3 g - 3 < 1$

Move all terms not containing $g$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$- 3 g < 1 + 3$

Add $1$ and $3$ .

$- 3 g < 4$

Divide each term in $- 3 g < 4$ by $- 3$ and simplify.

Divide each term in $- 3 g < 4$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 g}{- 3} > \frac{4}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 g}{- 3} > \frac{4}{- 3}$

Divide $g$ by $1$ .

$g > \frac{4}{- 3}$

Simplify the right side.

Move the negative in front of the fraction.

$g > - \frac{4}{3}$

The result can be shown in multiple forms.

Inequality Form:

$g > - \frac{4}{3}$

Interval Notation:

$(- \frac{4}{3}, \infty)$

Solve the Inequality for g 4g-3<7g+1

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