Solve the Inequality for g g/-5<-18

$\frac{g}{- 5} < - 18$

Multiply both sides by $- 5$ .

$\frac{g}{- 5} \cdot - 5 > - 18 \cdot - 5$

Simplify.

Simplify the left side.

Simplify $\frac{g}{- 5} \cdot - 5$ .

Cancel the common factor of $5$ .

Factor $5$ out of $- 5$ .

$\frac{g}{5 (- 1)} \cdot - 5 > - 18 \cdot - 5$

Factor $5$ out of $- 5$ .

$\frac{g}{5 \cdot - 1} \cdot (5 \cdot - 1) > - 18 \cdot - 5$

Cancel the common factor.

$\frac{g}{5 \cdot - 1} \cdot (5 \cdot - 1) > - 18 \cdot - 5$

Rewrite the expression.

$\frac{g}{- 1} \cdot - 1 > - 18 \cdot - 5$

Combine $\frac{g}{- 1}$ and $- 1$ .

$\frac{g \cdot - 1}{- 1} > - 18 \cdot - 5$

Simplify the expression.

Move the negative one from the denominator of $\frac{g \cdot - 1}{- 1}$ .

$- 1 \cdot (g \cdot - 1) > - 18 \cdot - 5$

Rewrite $- 1 \cdot (g \cdot - 1)$ as $- (g \cdot - 1)$ .

$- (g \cdot - 1) > - 18 \cdot - 5$

Move $- 1$ to the left of $g$ .

$- (- 1 \cdot g) > - 18 \cdot - 5$

Rewrite $- 1 g$ as $- g$ .

$- - g > - 18 \cdot - 5$

Multiply $- - g$ .

Multiply $- 1$ by $- 1$ .

$1 g > - 18 \cdot - 5$

Multiply $g$ by $1$ .

$g > - 18 \cdot - 5$

Simplify the right side.

Multiply $- 18$ by $- 5$ .

$g > 90$

The result can be shown in multiple forms.

Inequality Form:

$g > 90$

Interval Notation:

$(90, \infty)$