Solve the Inequality for h -12>-9h

$- 12 > - 9 h$

Rewrite so $h$ is on the left side of the inequality.

$- 9 h < - 12$

Divide each term in $- 9 h < - 12$ by $- 9$ and simplify.

Divide each term in $- 9 h < - 12$ by $- 9$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 9 h}{- 9} > \frac{- 12}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 h}{- 9} > \frac{- 12}{- 9}$

Divide $h$ by $1$ .

$h > \frac{- 12}{- 9}$

Simplify the right side.

Cancel the common factor of $- 12$ and $- 9$ .

Factor $- 3$ out of $- 12$ .

$h > \frac{- 3 (4)}{- 9}$

Cancel the common factors.

Factor $- 3$ out of $- 9$ .

$h > \frac{- 3 \cdot 4}{- 3 \cdot 3}$

Cancel the common factor.

$h > \frac{- 3 \cdot 4}{- 3 \cdot 3}$

Rewrite the expression.

$h > \frac{4}{3}$

The result can be shown in multiple forms.

Inequality Form:

$h > \frac{4}{3}$

Interval Notation:

$(\frac{4}{3}, \infty)$

Solve the Inequality for h -12>-9h

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