Solve the Inequality for h 3/5h>=-3

$\frac{3}{5} h \geq - 3$

Step 1

Multiply each term in $\frac{3}{5} h \geq - 3$ by $\frac{5}{3}$ .

$\frac{3}{5} h \frac{5}{3} \geq - 3 (\frac{5}{3})$

Step 2

Simplify the left side.

Combine $\frac{3}{5}$ and $h$ .

$\frac{3 h}{5} \cdot \frac{5}{3} \geq - 3 (\frac{5}{3})$

Cancel the common factor of $3$ .

Factor $3$ out of $3 h$ .

$\frac{3 (h)}{5} \cdot \frac{5}{3} \geq - 3 (\frac{5}{3})$

Cancel the common factor.

$\frac{3 h}{5} \cdot \frac{5}{3} \geq - 3 (\frac{5}{3})$

Rewrite the expression.

$\frac{h}{5} \cdot 5 \geq - 3 (\frac{5}{3})$

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{h}{5} \cdot 5 \geq - 3 (\frac{5}{3})$

Rewrite the expression.

$h \geq - 3 (\frac{5}{3})$

Step 3

Simplify the right side.

Cancel the common factor of $3$ .

Factor $3$ out of $- 3$ .

$h \geq 3 (- 1) \frac{5}{3}$

Cancel the common factor.

$h \geq 3 \cdot - 1 \frac{5}{3}$

Rewrite the expression.

$h \geq - 1 \cdot 5$

Multiply $- 1$ by $5$ .

$h \geq - 5$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$h \geq - 5$

Interval Notation:

$[- 5, \infty)$