Solve the Inequality for h 5(2h+8)<60

$5 (2 h + 8) < 60$

Divide each term in $5 (2 h + 8) < 60$ by $5$ and simplify.

Divide each term in $5 (2 h + 8) < 60$ by $5$ .

$\frac{5 (2 h + 8)}{5} < \frac{60}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 (2 h + 8)}{5} < \frac{60}{5}$

Divide $2 h + 8$ by $1$ .

$2 h + 8 < \frac{60}{5}$

Simplify the right side.

Divide $60$ by $5$ .

$2 h + 8 < 12$

Move all terms not containing $h$ to the right side of the inequality.

Subtract $8$ from both sides of the inequality.

$2 h < 12 - 8$

Subtract $8$ from $12$ .

$2 h < 4$

Divide each term in $2 h < 4$ by $2$ and simplify.

Divide each term in $2 h < 4$ by $2$ .

$\frac{2 h}{2} < \frac{4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 h}{2} < \frac{4}{2}$

Divide $h$ by $1$ .

$h < \frac{4}{2}$

Simplify the right side.

Divide $4$ by $2$ .

$h < 2$

The result can be shown in multiple forms.

Inequality Form:

$h < 2$

Interval Notation:

$(- \infty, 2)$