Solve the Inequality for j -3/4j>=12

$- \frac{3}{4} j \geq 12$

Multiply each term in $- \frac{3}{4} j \geq 12$ by $- \frac{4}{3}$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$- \frac{3}{4} j (- \frac{4}{3}) \leq 12 (- \frac{4}{3})$

Simplify the left side.

Combine $j$ and $\frac{3}{4}$ .

$- \frac{j \cdot 3}{4} (- \frac{4}{3}) \leq 12 (- \frac{4}{3})$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{j \cdot 3}{4}$ into the numerator.

$\frac{- j \cdot 3}{4} (- \frac{4}{3}) \leq 12 (- \frac{4}{3})$

Move the leading negative in $- \frac{4}{3}$ into the numerator.

$\frac{- j \cdot 3}{4} \cdot \frac{- 4}{3} \leq 12 (- \frac{4}{3})$

Factor $3$ out of $- j \cdot 3$ .

$\frac{3 \cdot (- j)}{4} \cdot \frac{- 4}{3} \leq 12 (- \frac{4}{3})$

Cancel the common factor.

$\frac{3 \cdot (- j)}{4} \cdot \frac{- 4}{3} \leq 12 (- \frac{4}{3})$

Rewrite the expression.

$\frac{- j}{4} \cdot - 4 \leq 12 (- \frac{4}{3})$

Cancel the common factor of $4$ .

Factor $4$ out of $- 4$ .

$\frac{- j}{4} \cdot (4 (- 1)) \leq 12 (- \frac{4}{3})$

Cancel the common factor.

$\frac{- j}{4} \cdot (4 \cdot - 1) \leq 12 (- \frac{4}{3})$

Rewrite the expression.

$- j \cdot - 1 \leq 12 (- \frac{4}{3})$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 j \leq 12 (- \frac{4}{3})$

Multiply $j$ by $1$ .

$j \leq 12 (- \frac{4}{3})$

Simplify the right side.

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{4}{3}$ into the numerator.

$j \leq 12 (\frac{- 4}{3})$

Factor $3$ out of $12$ .

$j \leq 3 (4) \frac{- 4}{3}$

Cancel the common factor.

$j \leq 3 \cdot 4 \frac{- 4}{3}$

Rewrite the expression.

$j \leq 4 \cdot - 4$

Multiply $4$ by $- 4$ .

$j \leq - 16$

The result can be shown in multiple forms.

Inequality Form:

$j \leq - 16$

Interval Notation:

$(- \infty, - 16]$

Solve the Inequality for j -3/4j>=12

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