Solve the Inequality for k 10/3k>=-10

$\frac{10}{3} k \geq - 10$

Step 1

Multiply each term in $\frac{10}{3} k \geq - 10$ by $\frac{3}{10}$ .

$\frac{10}{3} k \frac{3}{10} \geq - 10 (\frac{3}{10})$

Step 2

Simplify the left side.

Combine $\frac{10}{3}$ and $k$ .

$\frac{10 k}{3} \cdot \frac{3}{10} \geq - 10 (\frac{3}{10})$

Cancel the common factor of $10$ .

Factor $10$ out of $10 k$ .

$\frac{10 (k)}{3} \cdot \frac{3}{10} \geq - 10 (\frac{3}{10})$

Cancel the common factor.

$\frac{10 k}{3} \cdot \frac{3}{10} \geq - 10 (\frac{3}{10})$

Rewrite the expression.

$\frac{k}{3} \cdot 3 \geq - 10 (\frac{3}{10})$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{k}{3} \cdot 3 \geq - 10 (\frac{3}{10})$

Rewrite the expression.

$k \geq - 10 (\frac{3}{10})$

Step 3

Simplify the right side.

Cancel the common factor of $10$ .

Factor $10$ out of $- 10$ .

$k \geq 10 (- 1) \frac{3}{10}$

Cancel the common factor.

$k \geq 10 \cdot - 1 \frac{3}{10}$

Rewrite the expression.

$k \geq - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$k \geq - 3$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$k \geq - 3$

Interval Notation:

$[- 3, \infty)$