Solve the Inequality for k 3(k-9)>3k+6

$3 (k - 9) > 3 k + 6$

Simplify $3 (k - 9)$ .

Rewrite.

$0 + 0 + 3 (k - 9) > 3 k + 6$

Simplify by adding zeros.

$3 (k - 9) > 3 k + 6$

Apply the distributive property.

$3 k + 3 \cdot - 9 > 3 k + 6$

Multiply $3$ by $- 9$ .

$3 k - 27 > 3 k + 6$

Move all terms containing $k$ to the left side of the inequality.

Subtract $3 k$ from both sides of the inequality.

$3 k - 27 - 3 k > 6$

Combine the opposite terms in $3 k - 27 - 3 k$ .

Subtract $3 k$ from $3 k$ .

$0 - 27 > 6$

Subtract $27$ from $0$ .

$- 27 > 6$

Since $- 27 < 6$ , there are no solutions.

No solution