Solve the Inequality for k 6(k-11)>12

$6 (k - 11) > 12$

Step 1

Divide each term in $6 (k - 11) > 12$ by $6$ and simplify.

Divide each term in $6 (k - 11) > 12$ by $6$ .

$\frac{6 (k - 11)}{6} > \frac{12}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 (k - 11)}{6} > \frac{12}{6}$

Divide $k - 11$ by $1$ .

$k - 11 > \frac{12}{6}$

Simplify the right side.

Divide $12$ by $6$ .

$k - 11 > 2$

Step 2

Move all terms not containing $k$ to the right side of the inequality.

Add $11$ to both sides of the inequality.

$k > 2 + 11$

Add $2$ and $11$ .

$k > 13$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$k > 13$

Interval Notation:

$(13, \infty)$