Solve the Inequality for k 7<-(-k-3)+2

$7 < - (- k - 3) + 2$

Rewrite so $k$ is on the left side of the inequality.

$- (- k - 3) + 2 > 7$

Simplify $- (- k - 3) + 2$ .

Simplify each term.

Apply the distributive property.

$- - k - - 3 + 2 > 7$

Multiply $- - k$ .

Multiply $- 1$ by $- 1$ .

$1 k - - 3 + 2 > 7$

Multiply $k$ by $1$ .

$k - - 3 + 2 > 7$

Multiply $- 1$ by $- 3$ .

$k + 3 + 2 > 7$

Add $3$ and $2$ .

$k + 5 > 7$

Move all terms not containing $k$ to the right side of the inequality.

Subtract $5$ from both sides of the inequality.

$k > 7 - 5$

Subtract $5$ from $7$ .

$k > 2$

The result can be shown in multiple forms.

Inequality Form:

$k > 2$

Interval Notation:

$(2, \infty)$