Solve the Inequality for k 8k-3>9k+10

$8 k - 3 > 9 k + 10$

Move all terms containing $k$ to the left side of the inequality.

Subtract $9 k$ from both sides of the inequality.

$8 k - 3 - 9 k > 10$

Subtract $9 k$ from $8 k$ .

$- k - 3 > 10$

Move all terms not containing $k$ to the right side of the inequality.

Add $3$ to both sides of the inequality.

$- k > 10 + 3$

Add $10$ and $3$ .

$- k > 13$

Divide each term in $- k > 13$ by $- 1$ and simplify.

Divide each term in $- k > 13$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- k}{- 1} < \frac{13}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{k}{1} < \frac{13}{- 1}$

Divide $k$ by $1$ .

$k < \frac{13}{- 1}$

Simplify the right side.

Divide $13$ by $- 1$ .

$k < - 13$

The result can be shown in multiple forms.

Inequality Form:

$k < - 13$

Interval Notation:

$(- \infty, - 13)$

Solve the Inequality for k 8k-3>9k+10

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