Solve the Inequality for k k-17<=-(17-k)

$k - 17 \leq - (17 - k)$

Simplify $- (17 - k)$ .

Rewrite.

$k - 17 \leq 0 + 0 - (17 - k)$

Simplify by adding zeros.

$k - 17 \leq - (17 - k)$

Apply the distributive property.

$k - 17 \leq - 1 \cdot 17 - - k$

Multiply $- 1$ by $17$ .

$k - 17 \leq - 17 - - k$

Multiply $- - k$ .

Multiply $- 1$ by $- 1$ .

$k - 17 \leq - 17 + 1 k$

Multiply $k$ by $1$ .

$k - 17 \leq - 17 + k$

Move all terms containing $k$ to the left side of the inequality.

Subtract $k$ from both sides of the inequality.

$k - 17 - k \leq - 17$

Combine the opposite terms in $k - 17 - k$ .

Subtract $k$ from $k$ .

$0 - 17 \leq - 17$

Subtract $17$ from $0$ .

$- 17 \leq - 17$

Since $- 17 = - 17$ , the equation will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$