Solve the Inequality for m 3m-3(m+8)>3m

$3 m - 3 (m + 8) > 3 m$

Step 1

Simplify $3 m - 3 (m + 8)$ .

Simplify each term.

Apply the distributive property.

$3 m - 3 m - 3 \cdot 8 > 3 m$

Multiply $- 3$ by $8$ .

$3 m - 3 m - 24 > 3 m$

Simplify by adding terms.

Subtract $3 m$ from $3 m$ .

$0 - 24 > 3 m$

Subtract $24$ from $0$ .

$- 24 > 3 m$

Step 2

Rewrite so $m$ is on the left side of the inequality.

$3 m < - 24$

Step 3

Divide each term in $3 m < - 24$ by $3$ and simplify.

Divide each term in $3 m < - 24$ by $3$ .

$\frac{3 m}{3} < \frac{- 24}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 m}{3} < \frac{- 24}{3}$

Divide $m$ by $1$ .

$m < \frac{- 24}{3}$

Simplify the right side.

Divide $- 24$ by $3$ .

$m < - 8$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$m < - 8$

Interval Notation:

$(- \infty, - 8)$