Solve the Inequality for m log base 3 of 27<m

$\log_{3} (27) < m$

Rewrite so $m$ is on the left side of the inequality.

$m > \log_{3} (27)$

Logarithm base $3$ of $27$ is $3$ .

$m > 3$

The result can be shown in multiple forms.

Inequality Form:

$m > 3$

Interval Notation:

$(3, \infty)$