Solve the Inequality for n 32-5n>=7-5(n-5)

$32 - 5 n \geq 7 - 5 (n - 5)$

Simplify $7 - 5 (n - 5)$ .

Simplify each term.

Apply the distributive property.

$32 - 5 n \geq 7 - 5 n - 5 \cdot - 5$

Multiply $- 5$ by $- 5$ .

$32 - 5 n \geq 7 - 5 n + 25$

Add $7$ and $25$ .

$32 - 5 n \geq - 5 n + 32$

Move all terms containing $n$ to the left side of the inequality.

Add $5 n$ to both sides of the inequality.

$32 - 5 n + 5 n \geq 32$

Combine the opposite terms in $32 - 5 n + 5 n$ .

Add $- 5 n$ and $5 n$ .

$32 + 0 \geq 32$

Add $32$ and $0$ .

$32 \geq 32$

Since $32 = 32$ , the equation will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$