Solve the Inequality for n 4n+3<6n+8-2n

$4 n + 3 < 6 n + 8 - 2 n$

Step 1

Rewrite so $n$ is on the left side of the inequality.

$6 n + 8 - 2 n > 4 n + 3$

Step 2

Subtract $2 n$ from $6 n$ .

$4 n + 8 > 4 n + 3$

Step 3

Move all terms containing $n$ to the left side of the inequality.

Subtract $4 n$ from both sides of the inequality.

$4 n + 8 - 4 n > 3$

Combine the opposite terms in $4 n + 8 - 4 n$ .

Subtract $4 n$ from $4 n$ .

$0 + 8 > 3$

Add $0$ and $8$ .

$8 > 3$

Step 4

Since $8 > 3$ , the inequality will always be true.

Always true

Step 5

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$