Solve the Inequality for n n/-3>=1

$\frac{n}{- 3} \geq 1$

Multiply both sides by $- 3$ .

$\frac{n}{- 3} \cdot - 3 \leq 1 \cdot - 3$

Simplify.

Simplify the left side.

Simplify $\frac{n}{- 3} \cdot - 3$ .

Cancel the common factor of $3$ .

Factor $3$ out of $- 3$ .

$\frac{n}{3 (- 1)} \cdot - 3 \leq 1 \cdot - 3$

Factor $3$ out of $- 3$ .

$\frac{n}{3 \cdot - 1} \cdot (3 \cdot - 1) \leq 1 \cdot - 3$

Cancel the common factor.

$\frac{n}{3 \cdot - 1} \cdot (3 \cdot - 1) \leq 1 \cdot - 3$

Rewrite the expression.

$\frac{n}{- 1} \cdot - 1 \leq 1 \cdot - 3$

Combine $\frac{n}{- 1}$ and $- 1$ .

$\frac{n \cdot - 1}{- 1} \leq 1 \cdot - 3$

Simplify the expression.

Move the negative one from the denominator of $\frac{n \cdot - 1}{- 1}$ .

$- 1 \cdot (n \cdot - 1) \leq 1 \cdot - 3$

Rewrite $- 1 \cdot (n \cdot - 1)$ as $- (n \cdot - 1)$ .

$- (n \cdot - 1) \leq 1 \cdot - 3$

Move $- 1$ to the left of $n$ .

$- (- 1 \cdot n) \leq 1 \cdot - 3$

Rewrite $- 1 n$ as $- n$ .

$- - n \leq 1 \cdot - 3$

Multiply $- - n$ .

Multiply $- 1$ by $- 1$ .

$1 n \leq 1 \cdot - 3$

Multiply $n$ by $1$ .

$n \leq 1 \cdot - 3$

Simplify the right side.

Multiply $- 3$ by $1$ .

$n \leq - 3$

The result can be shown in multiple forms.

Inequality Form:

$n \leq - 3$

Interval Notation:

$(- \infty, - 3]$