Solve the Inequality for n n/3+2>0

$\frac{n}{3} + 2 > 0$

Step 1

Subtract $2$ from both sides of the inequality.

$\frac{n}{3} > - 2$

Step 2

Multiply both sides by $3$ .

$\frac{n}{3} \cdot 3 > - 2 \cdot 3$

Step 3

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{n}{3} \cdot 3 > - 2 \cdot 3$

Rewrite the expression.

$n > - 2 \cdot 3$

$n > - 2 \cdot 3$

$n > - 2 \cdot 3$

Simplify the right side.

Multiply $- 2$ by $3$ .

$n > - 6$

$n > - 6$

$n > - 6$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$n > - 6$

Interval Notation:

$(- 6, \infty)$

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