Solve the Inequality for p 12p<96

$12 p < 96$

Step 1

Divide each term in $12 p < 96$ by $12$ .

$\frac{12 p}{12} < \frac{96}{12}$

Step 2

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 p}{12} < \frac{96}{12}$

Divide $p$ by $1$ .

$p < \frac{96}{12}$

$p < \frac{96}{12}$

$p < \frac{96}{12}$

Step 3

Simplify the right side.

Divide $96$ by $12$ .

$p < 8$

$p < 8$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$p < 8$

Interval Notation:

$(- \infty, 8)$

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